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spring reverb driver not working. help with schematic?
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rjd2



Joined: Sep 02, 2007
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Location: philly

PostPosted: Mon Aug 10, 2009 1:50 pm    Post subject: spring reverb driver not working. help with schematic? Reply with quote  Mark this post and the followings unread

hi folks, im wondering if you can help me. i built this spring reverb driver(image attached), but it doesnt seem to be driving. output signal is dry. if i sweep thru the "depth" pot, i get a faint sort of phasing sound at about 2/3 of the way thru.

i wired all the connections exactly as i read them in the schematic, both in regards to pots/jacks, and IC's. so none of the unused pins of IC's are tied off(should they be to ground? -V?)

also, should any of the pot pins be referenced to ground or -V? thanks for the help.


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andrewF



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PostPosted: Mon Aug 10, 2009 4:32 pm    Post subject: Reply with quote  Mark this post and the followings unread

Sorry if this seems too obvious but its not marked on the schematic, did you connect the power pins of the 5532?
Pins 1&8 of the 386 can be left unconnected or you can connect a cap across them, this article explains a bit - 386 amp, probably not necessary at this stage, plenty of other things to check.
R1 on the schematic is sending a dry signal straight to the output opamp, maybe worth disconnecting this resistor until you get the circuit working (personally i would remove it forever or put an attenuating pot in the way)
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rjd2



Joined: Sep 02, 2007
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PostPosted: Mon Aug 10, 2009 5:56 pm    Post subject: Reply with quote  Mark this post and the followings unread

no, please-nothings too obvious for me!

yes, both the 5532's and the 386(i apparently have a jrc 386bd here) have their power pins right. this was really the only thing i knew how to check on my bench,cause i cant plug it into the spring AND have it on the bench.

i'll try disconnecting R1 and see where that gets me.

im thinking that my wiring is probably the next suspect aspect of this?
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rjd2



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PostPosted: Mon Aug 10, 2009 6:30 pm    Post subject: Reply with quote  Mark this post and the followings unread

ok, HERE"S a green question:

on the potentiomter diagram, there are 3 lines coming out. 2 out the "sides of the box", and one that's an arrow towards the middle. is the arrow towards the middle the middle pin, and the lines coming out the sides the L and R pins of the pot? this is now seeming very wrong. and yet how i wired the pots for some reason...

sorry, im not coming from a "real" EE background. i can read the diagrams on most DIY instructions, but this is the first thing i've built without a pre-made pcb.
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andrewF



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PostPosted: Mon Aug 10, 2009 7:11 pm    Post subject: Reply with quote  Mark this post and the followings unread

Yes the line with the arrow connects to the middle pin.
It is important to get this connection right, the outerpins don't matter other than deciding which way to turn the pot for min/max values.

On VR1, the centre pin connects to R8, one of the outer pins to ground, the other to the input. When a pot is connected like this (one pin to ground) it acts as a divider or attenuator. for example, when set halfway it will reduce the input signal by 50%.

On VR2, the centre pin and one of the outer pins are connected together and connected to R9 and pin 7 of U1B. The other pin is connected to pin6 of U1B and R3. This pot is acting as a rheostat, basically it is just a resistor that you can adjust to any value between 0 and 100k Ohm.
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andrewF



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PostPosted: Mon Aug 10, 2009 7:20 pm    Post subject: Reply with quote  Mark this post and the followings unread

rjd2 wrote:

sorry, im not coming from a "real" EE background. i can read the diagrams on most DIY instructions, but this is the first thing i've built without a pre-made pcb.

few of us are, I was well over 30 the 1st time I held a soldering iron and discovered the pretty coloured stripes on resistors actually meant something Surprised
Trouble-shooting nonworking ccts is the best way to learn....tho an oscilloscope makes life much easier.
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rjd2



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PostPosted: Mon Aug 10, 2009 7:52 pm    Post subject: Reply with quote  Mark this post and the followings unread

ive got a scope, dvm, desoldering and soldering iron, so im pretty good to go on the toys! ill keep plugging on this, thanks for the help.
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daverj



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PostPosted: Tue Aug 11, 2009 11:55 am    Post subject: Reply with quote  Mark this post and the followings unread

rjd2 wrote:
yes, both the 5532's and the 386(i apparently have a jrc 386bd here) have their power pins right. this was really the only thing i knew how to check on my bench,cause i cant plug it into the spring AND have it on the bench.


Is pin 4 of the NE5532 going to a negative power supply? The 386 can run off of plus power and ground because it internally biases the input, but the NE5532 is a normal op amp and the way this circuit is laid out it needs to use bipolar power supplies (ie: +/-12 or +/-15)
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rjd2



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PostPosted: Tue Aug 11, 2009 1:07 pm    Post subject: Reply with quote  Mark this post and the followings unread

i have pins 4 and 8 of the 5532's going to -V and +V respectively.

and pin 6 of the 386 going to +V.

however, i dont have any of their pins connected to ground. which pins would be ground?
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daverj



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PostPosted: Tue Aug 11, 2009 1:25 pm    Post subject: Reply with quote  Mark this post and the followings unread

pin 2 & 4 of the 386 go to ground. None of the NE5532 pins go to ground. Though it would be a good idea to have a pair of .1uf caps between the power pins and ground.

You said you have a scope... With everything connected, do you have an audio waveform showing at the input to the spring (coming from the 386)? And is there an audio waveform at pin 7 of the NE5532?
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Uncle Krunkus
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PostPosted: Wed Aug 12, 2009 5:07 am    Post subject: Reply with quote  Mark this post and the followings unread

Hey rjd2,
You do know that -V is not the same as ground yeah?
What daverj was saying may not have made you realise this.
The NE5532 actualy needs a bi-polar supply. That means -V, Ground & +V.
Three connections.
The 386 will just use Ground and +V.
Does that make sense?

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Uncle Krunkus
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PostPosted: Wed Aug 12, 2009 5:09 am    Post subject: Reply with quote  Mark this post and the followings unread

The thing I'm unsure about is the "S.O.T." on R5 and C5.
Does anyone know what that means?

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esnabez



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PostPosted: Wed Aug 12, 2009 7:53 am    Post subject: Reply with quote  Mark this post and the followings unread

S.O.T stands for "select on test". Those components are variable depending on which reverb tank you choose.
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rjd2



Joined: Sep 02, 2007
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PostPosted: Wed Aug 12, 2009 9:53 am    Post subject: Reply with quote  Mark this post and the followings unread

Uncle Krunkus wrote:
Hey rjd2,
You do know that -V is not the same as ground yeah?
What daverj was saying may not have made you realise this.
The NE5532 actualy needs a bi-polar supply. That means -V, Ground & +V.
Three connections.
The 386 will just use Ground and +V.
Does that make sense?


yea, got that. thanks. for the 5532, ive got -V and +V, no ground ref.

for the 386, ive now got pins 2 and 4 to ground, pin 6 to +V.

im gonna do the scope test and see if i can get from input to spring send in later today...
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Uncle Krunkus
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PostPosted: Wed Aug 12, 2009 3:06 pm    Post subject: Reply with quote  Mark this post and the followings unread

esnabez wrote:
S.O.T stands for "select on test". Those components are variable depending on which reverb tank you choose.


Oh,... Thanks for that. Hadn't come across it before.
And thanks for this thread/schem rjd2, I've actually got a nice tank which I salvaged from an old Peavey desk, and that schem is a nice simple one to start playing around with.

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rjd2



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PostPosted: Wed Aug 12, 2009 4:49 pm    Post subject: Reply with quote  Mark this post and the followings unread

ok, so i believe i have isolated the problem to the output end.

if i send a square wave to the input jack, i get a square wave at "reverb in".

however, if i send square wave to the "reverb out" pin of the circuit, i dont seem to get a square wave at the output jack.

i should, right?

so i think i'll send square wave to "reverb out", and trace it to see where it dies?
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Uncle Krunkus
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PostPosted: Wed Aug 12, 2009 6:21 pm    Post subject: Reply with quote  Mark this post and the followings unread

Okay,
check the mute switch isn't closed,
check the reverb level pot is up,
did you use the same resistor values?
electrolytic cap the right way round?
IC pin numbering okay?

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rjd2



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PostPosted: Wed Aug 12, 2009 6:42 pm    Post subject: Reply with quote  Mark this post and the followings unread

thanks, unk!

so i had forgotten that i had disconnected the input at pin 2 of the last 5532.

so now, i can send a square wave to "reverb out" pin, and then see that square wave at the output jack.

as ive verified the same thing from input jack, to "reverb in" pin, i think i can verify that the driver is at least built properly.

now, i guess its up to the tank.....wish me luck!

i believe
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Uncle Krunkus
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PostPosted: Wed Aug 12, 2009 7:47 pm    Post subject: Reply with quote  Mark this post and the followings unread

Well, it's still a good idea to test it with R1 not connected to the 5532, so you can hear only what's coming through the tank. But make sure R10 and R2 are still connected to pin 2.
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