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 Forum index » DIY Hardware and Software » Supercollider
is there a .stop method?
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flies



Joined: May 20, 2008
Posts: 29
Location: NJ

PostPosted: Sun Aug 30, 2009 10:47 am    Post subject: is there a .stop method?
Subject description: more noob questions
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going through the getting started tutorials here.

let's say i defined an object, x = { SinOsc.ar(400) };

x.play; will set my sine wave going. how do i stop it? is there a x.kill method or the like? (i know alt . will stop everything (on PC), but i'm looking for a less drastic solution.)

also: is there a way to change the pitch of x as written? if not, how would i define an object so that i could say x.changePitch(200); or similar? even better, how can i say x.changePitch(200+(20*SinOsc.kr(1))) ?

am noob. plz helps.
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dewdrop_world



Joined: Aug 28, 2006
Posts: 858
Location: Guangzhou, China
Audio files: 4

PostPosted: Mon Aug 31, 2009 5:49 am    Post subject: Reply with quote  Mark this post and the followings unread

x is a function - no way to stop a function.

Code:
y = x.play;


Now 'y' is a synth, and you can .free it, and also use .set to change control inputs etc.

Code:
// collapsing x and y into one
y = { |freq = 400| SinOsc.ar(freq) }.play;

y.set(\freq, 800);


You can't directly add new units into a synth while it's playing, but you can map an input to a control bus and play whatever you want onto that bus.

Code:
c = Bus.control(s, 1);
y.set(\freq, c.asMap);   // or y.map(\freq, c);
z = { SinOsc.kr(1, 0, mul: 20, add: 200) }.play(outbus: c);


James

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flies



Joined: May 20, 2008
Posts: 29
Location: NJ

PostPosted: Mon Aug 31, 2009 10:14 am    Post subject: Reply with quote  Mark this post and the followings unread

great. thanks!
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