| Author |
Message |
Ronja
Joined: Mar 25, 2021
Posts: 3
Location: Sweden
|
 Posted: Thu Mar 25, 2021 6:03 am Post subject:
SOLVED!!! CGS06 Burst Gen - Why no output on pin 3? |
  |
|
Hiya. Long time lurker, but first time poster.
I just finished a stripboard layout where I combine the Yusynth Random Gates with the CGS06 Burs Generator. As I finished it I saw that there is no connection on pin 3 of the 4017, which is the first output on the chip.
I tried to find any info in the build documents or from searching on google, but there was no mentioning of it I could find.
Does anyone know why it is build that way? I might be wrong, but it should mean also that the first pulse of the burst will not be close to the trigger in time, but slightly after?
Best regards
Ronja
Last edited by Ronja on Tue Mar 30, 2021 6:50 am; edited 1 time in total |
|
|
Back to top
|
|
 |
Hubaswift
Joined: Jul 06, 2016
Posts: 91
Location: Canada
|
| Posted: Mon Mar 29, 2021 8:24 pm Post subject:
|
|
|
| From the looks of things, Q0, or pin 3 on the 4017 serves as a starting point, the step it defaults to when it is reset. Because of this when a trigger is applied to the 4017 and it starts clocking through its steps, the first step it changes to isn't actually Q0, it's Q1. |
|
|
Back to top
|
|
|
Ronja
Joined: Mar 25, 2021
Posts: 3
Location: Sweden
|
| Posted: Tue Mar 30, 2021 6:49 am Post subject:
|
|
|
| Hubaswift wrote: | | From the looks of things, Q0, or pin 3 on the 4017 serves as a starting point, the step it defaults to when it is reset. Because of this when a trigger is applied to the 4017 and it starts clocking through its steps, the first step it changes to isn't actually Q0, it's Q1. |
The 4017 has 10 steps that is cycles through: Q0-Q9. Look at any 4017-based sequencer (like the Baby10: https://hackaday.com/2016/01/14/oh-baby-baby10-build-a-classic-analog-music-sequencer/ or Ken Stones own take on the original SERGE 10 step sequenser: https://sdiy.info/wiki/CGS_gate_sequencer ) and youll see that it is used for the first step. When the chip resets it goes back to step one (which is Q0) and start cycling from that. Hence the question why the burst generator does not.
This got me thinking, and when looking at the schematic again I realize I did misunderstand it totally. I should heve posted it in the original post, but figured ppl in this forum knew wheere to find the schematics. https://sdiy.info/wiki/CGS_burst_generator
Since I have only used the 4017 for making sequencers etc, I had that mindset when I looked at this circuit. But now when I looked at it for the 100th time I finally got it: The 4017 is not outputting any pulses. It is merely used to decide how many of the clock pulses should be let through before resetting, which is a totally different circuit. The reset work like this on the 4017: if no step is connected to reset, it will play all 10 steps (Q0-Q9)and reset to Q0 and start over. If any step is connected to reset it will play all the prior steps, but not the step connected to reset. So if the second step (Q1) is connected to reset it will only play the first step (Q0).
Sometimes you need a little time to understand things correctly. Thanx |
|
|
Back to top
|
|
|
|
Forum index » DIY Hardware and Software » Ken Stone designs - CGS
FAQ
Calendar
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
Chat Room
